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- The people go outside?
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- Hi Jesse, I just came across your site while I was searching for more details on the influence function. You have mentioned that "calculating the influence function exactly is NP-hard" -...
- The Erlang documentation covers its approach to in-place code upgrades here: http://erlang.org/doc/design_principles/part_frame.html . In particular, see the sections "Releases" and...
1 year ago
I look forward to the rest of this series of posts. I really enjoy reading your blog man, keep up the good work! Another area I'd love to see you write about that's also closely related to set theory is neural networks and other learning algorithms. Particularly as they apply to collaborative filtering. I think there's huge potential in collaborative filtering for web 2.0ish websites, but there are few sites that are really focused on the problem (perhaps because it's very complicated).
Also, one completely unrelated side note: I was at Facebook a few days ago and they all knew of you/your blog! Your reputation precedes you =p.
1 year ago
Glad to hear people at Facebook know my name! Too bad they didn't want to hire me. :P
1 year ago
"Vertices could be cities and edges could be interstate highways."
instead of
"Edges could be cities and edges could be interstate highways."
1 year ago
Perhaps you could write E(v1, v3, v2), which might reduce to E(v1, v2)?
I hope you understand what I'm trying to ask...(also, I'm sorry to ask an elementary question. you're not here to teach math. I'm trying to find an answer to it myself right now.)
1 year ago
You'd say there is a path from v<sub>1</sub> to v<sub>2</sub>, but not that there is an edge between them. IOW, the edge relationship is not necessary transitive. In fact, the edge set doesn't even need to be represented by ordered pairs, so it's not even necessarily a "relation" in the strict mathematical sense of the word, e.g., you might have multiple edges between two vertices.
Most people mean "simple graph" when they say graph, so these "pathological" cases (i.e., loops, multiple edges, etc.) are excluded from the outset.
That said, if you have a graph G = (V,E) you could define another graph G' = (V,E') whose edge relationship is v ~ w iff there is a path between v and w in G.
I'm not sure this is a very interesting graph, though. You'd basically take the connected components of G and turn them into complete graphs. So G' is always a disjoint union of some number of complete graphs. I don't think it tells you anything particularly useful about G.
Hope that helps.
- Jesse
1 year ago